chemistry

ammonia (NH3) chemically reacts with oxygen gas (O2) to produce nitric oxide (NO) and water (H2O). What mass of water is produced by the reaction of 1.09g of oxygen gas?

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  1. Just follow the steps.
    http://www.jiskha.com/science/chemistry/stoichiometry.html

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  2. 2NH3+5/2O2--->2NO+3H2O
    5/2X32 3X18
    80 54
    1.09 ?
    [APPROX 1]
    CROSS MUTIPPLY IF U TAKE IT AS 1.09
    1X54/80 THEN,1.09X54/80=0.73575
    =54/80
    =27/40
    =0.675

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  3. First, write a balanced chemical equation for the reaction:
    →+4NH35O2+4NO6H2O
    .
    The mole ratio of any two compounds in a chemical reaction is given by the ratio of the stoichiometric coefficients of those compounds in the balanced chemical equation. That means this equation is true:
    moles of
    H2O
    produced

    moles of
    NH3
    consumed
    =
    6

    4
    .
    Knowing this key equation, use the following plan to answer the question.
    Convert grams of ammonia consumed to moles using the molar mass of ammonia.
    Calculate moles of water produced from moles of ammonia consumed using the mole ratio above.
    Convert moles of water produced to grams using the molar mass of water.
    Step 1: Find the moles of ammonia consumed.
    You'll need the molar mass of ammonia:

    1
    ×
    molar mass of
    N
    +
    3
    ×
    molar mass of
    H

    1
    molar mass of
    NH3
    1
    ×
    14.0067·gmol−1
    +
    3
    ×
    1.00794·gmol−1

    17.03052·gmol−1
    Note: Be sure you use the atomic masses from the ALEKS
    Calculator or ALEKS Periodic Table and do not round early so
    that your answer has the correct number of significant digits.
    Use the molar mass to convert grams of ammonia consumed to moles of ammonia produced:
    moles of
    NH3
    consumed
    =
    (mass of
    NH3
    consumed)

    (molar mass of
    NH3
    )
    =
    9.05g17.03052·gmol−1
    =
    0.53140…mol
    .
    There are
    3
    significant digits in
    9.05g
    . That means there are
    3
    significant digits in your calculated answer for moles of ammonia. However, keep a few extra digits for now and only round your final answer.
    Step 2: Find the moles of water produced.
    Multiply the moles of ammonia consumed by the mole ratio:


    moles of
    H2O
    produced
    =
    (moles of
    NH3
    consumed)
    ×
    (moles of
    H2O
    produced)

    (moles of
    NH3
    consumed)
    =
    ×0.53140mol64
    =
    0.79710…mol
    .
    Because stoichiometric coefficients are exact numbers, the number of moles of water has the same number of significant digits as the number of moles of ammonia.
    Step 3: Find the mass of water produced.
    You'll need the molar mass of water:

    2
    ×
    molar mass of
    H
    +
    1
    ×
    molar mass of
    O

    1
    molar mass of
    H2O
    2
    ×
    1.00794·gmol−1
    +
    1
    ×
    15.9994·gmol−1

    18.01528·gmol−1
    Use the molar mass to convert moles of water produced to grams of water produced:
    mass of
    H2O
    produced
    =
    (moles of
    H2O
    produced)
    ×
    (molar mass of
    H2O
    )
    =
    ×0.79710mol18.01528·gmol−1
    =
    14.35998…g
    .
    There are
    3
    significant digits in your calculated answer for moles of water. That means there are
    3
    significant digits in your final calculated answer.
    Be sure to round your final answer correctly to
    3
    significant digits.

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