algebra

I need help with: solving and check for extraneous solutions.
sqrt y+9=1

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  1. Is your equation √(y+9) = 1?

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  2. I'll assume it is...

    First, square both sides to get

    y + 9 = 1
    y = -8

    Now plug that back into the original equation to see if it is extraneous. (An extraneous solution is one that does not work.)

    √(-8 + 9) = 1
    √(1) = 1

    That is correct, so the answer is y = 1.

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