A bullet of mass 10.8 g leaves a gun barrel with a velocity of 511 m/s. What is the bullet's kinetic energy? answer in joules
10.8g = 0.0108kg.
KE=0.5mV^2 = 0.5*0.0108*(511)^2=1410J.
hmm sum1 has the same ? as me?
To find the kinetic energy of the bullet, we can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given:
Mass of the bullet, m = 10.8 g = 0.0108 kg
Velocity of the bullet, v = 511 m/s
Plugging these values into the formula, we get:
Kinetic Energy = (1/2) * 0.0108 kg * (511 m/s)^2
Calculating this:
Kinetic Energy = (1/2) * 0.0108 * (511^2)
= 0.0054 * (261,121)
= 1,408.68 J
Therefore, the bullet's kinetic energy is 1,408.68 joules.
To find the kinetic energy of the bullet, we can use the formula:
Kinetic Energy = 1/2 * mass * velocity^2
First, let's convert the mass of the bullet from grams to kilograms. Since there are 1000 grams in a kilogram, the mass of the bullet is 10.8 g / 1000 = 0.0108 kg.
Next, we can substitute the values into the formula:
Kinetic Energy = 1/2 * 0.0108 kg * (511 m/s)^2
Now, we can calculate the kinetic energy:
Kinetic Energy = 1/2 * 0.0108 kg * (511 m/s)^2
= 1/2 * 0.0108 kg * 261121 m^2/s^2
= 1/2 * 2,819.26608 kg·m^2/s^2 (calculating the square of 511)
= 1,409.63304 J
Therefore, the kinetic energy of the bullet is approximately 1409.63304 joules.