3. A 2.0-kg brick has the dimensions 7.5 cm „e 15 cm „e 30.0 cm. What is the pressure (in SI units) the brick exerts when standing on its largest face?

Weight (M*g) divided by the largest face area, which is 0.045 square meters.

To calculate the pressure exerted by the brick, you need to use the equation:

Pressure = Force / Area

First, we need to calculate the force exerted by the brick. The force (weight) can be calculated using Newton's second law:

Force = Mass * Gravity

The mass of the brick is given as 2.0 kg, and the acceleration due to gravity is a constant value of approximately 9.8 m/s^2.

So the force exerted by the brick is:

Force = 2.0 kg * 9.8 m/s^2 = 19.6 N

Now, we need to find the area of the largest face of the brick. The largest face is the one with dimensions 15 cm x 30 cm.

To calculate the area, we convert the dimensions to meters (since SI units are used for pressure).

Length = 15 cm = 0.15 m
Width = 30 cm = 0.30 m

Area = Length * Width = 0.15 m * 0.30 m = 0.045 m^2

Finally, we can calculate the pressure:

Pressure = Force / Area = 19.6 N / 0.045 m^2

Therefore, the pressure exerted by the brick when standing on its largest face is:

Pressure ≈ 435 Pa (Pascals)