calc

Evaluate the given expression.

d
dx
[2(x2 + 3|x|)]
1

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  1. I am guessing you want the derivative of the piecewise-continuous function

    f(x) = 2(x^2 + 3|x|) ,

    but what does the "1" represent?

    If you want the derivative at x=1, you can remove the | | signs

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  2. For |x|, we have 2 situations.
    |x| = x, for x >= 0
    |x| = -x, for x < 0

    So:
    ¤ for x>=0:
    d/dx (2(x^2 + 3x)) = ?
    ¤ for x<0:
    d/dx (2(x^2 - 3x)) = ?

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