Questions Math
Which term in the expansion of ((1/2x^3)-(x^5))^8 is a constant?
THANKS!!
It is a constant when the expansion has the term 1/2x^3 raised to the power of 5 and (x^5) raised to the power of 3. The product is x^0 which makes the term constant.
The term is:
-C(8,3) * (1/(2x^3))^5 * (x^5)^3
=-(8!/(3!5!)) * 1/(32x^15) * (x^15) )
=-(56/32)
=-7/4
You can ask a new question or answer this question .
Similar Questions
Top answer:
the general term is ... term(r+1) = C(9,r) x^r ((-1/6)x^2)^(9-r) = C(9,r) (-1/6)^(9-r) x^r x^(18-2r)
Read more.
Top answer:
The constant term is the term where the power of x in the product (1/(3x²))^r*x^(15-r) is zero,
Read more.
Top answer:
for the first one, first of all, find the general term. I got C(7,r)x^(7-r)(3/x^2)^r =c(7,r)(3)^r
Read more.
Top answer:
1 x is variable 3,5,8 is exponents
Read more.
Top answer:
(3x - 5/x)^2 = 9x^2 -30 + 25/x^2 The constant term is -30. Do the multiplication by (3x - 5/x) eight
Read more.
Top answer:
(1/x^8) [ 3 x^10 +1 ]^8 now find the term in x^8 in the expansion of (3 x^10 + 1)^8 because when you
Read more.
Top answer:
When 'x' is not in the term, than x will have the same power in the numerator and denominator, and
Read more.
Top answer:
looks like you are studying the binomial theorem You MUST memorize some basic formulas e.g. for
Read more.