a100 grams bullets is fired from a 10kg gun with a speed of recoil of the gun
Duplicate post. Once again, used conservation of momentum.
By the way, is 100 g the mass of one bullet? Why do you use the plural bullets?
You should say either "100 g bullets ARE fired" or "a 100 g bullet IS fired."
To calculate the speed of recoil of the gun when a bullet is fired, we can use the principle of conservation of momentum. The total momentum before firing is equal to the total momentum after firing.
The momentum of an object is defined as the mass of the object multiplied by its velocity. In this case, the momentum before firing is the momentum of the gun, and after firing, it is the momentum of the gun and the bullet combined.
Given:
Mass of the bullet = 100 grams = 0.1 kg
Mass of the gun = 10 kg
Velocity of the bullet (assume muzzle velocity) = unknown
Let's assume the recoil velocity of the gun as V.
Before firing:
Momentum of the gun = (Mass of the gun) x (Initial velocity of the gun)
= 10 kg x V (Since the gun is initially at rest)
After firing:
Momentum of the gun and bullet combined = Momentum of the bullet + Momentum of the gun
= (Mass of the bullet) x (Velocity of the bullet) + (Mass of the gun) x (Final velocity of the gun)
= 0.1 kg x (Velocity of the bullet) + 10 kg x (-V) (Note: The negative sign indicates opposite direction)
According to the law of conservation of momentum,
Momentum before firing = Momentum after firing
10 kg x V = 0.1 kg x (Velocity of the bullet) - 10 kg x V
Simplifying the equation,
20 kg x V = 0.1 kg x (Velocity of the bullet)
Dividing both sides of the equation by 20 kg,
V = 0.1 kg x (Velocity of the bullet) / 20 kg
Therefore, the speed of recoil of the gun (V) can be calculated by dividing 0.1 kg multiplied by the velocity of the bullet by 20 kg.