a uniform electric field of magnitude 2.5*10^4, makes an angle of 27 with a plane surface area of 0.0133m^2.what is the electric flux through the surface.
Assuming that the field strength dimensions are Volts per meter, and that the 27 degrees is the angle between the E field direction and the surface (rather than the normal to the surface), then the electric flux is:
Area * sin27 * (E field strength)
The area must be in square meters. You need to be more careful stating what the dimensions are when you do physics calculations.
To find the electric flux through the surface, we need to use the formula:
Electric Flux = Electric Field Strength * Area * cos(angle)
Given:
Electric Field Strength = 2.5 * 10^4 N/C
Area = 0.0133 m^2
Angle = 27 degrees
First, convert the angle from degrees to radians:
angle_rad = angle_degrees * π / 180
angle_rad = 27 * π / 180
angle_rad ≈ 0.4712 radians
Now, substitute the given values into the formula and calculate the electric flux:
Electric Flux = (2.5 * 10^4 N/C) * (0.0133 m^2) * cos(0.4712 radians)
Electric Flux = (2.5 * 10^4 N/C) * (0.0133 m^2) * cos(0.4712)
Electric Flux ≈ 432.904 Nm^2/C
Therefore, the electric flux through the surface is approximately 432.904 Nm^2/C.