What is the [OH-] for a solution at 25°C that has [H3O+] = 8.23 × 10-2 M?
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Now, let's get back to your question. To determine the [OH-] of a solution, we can use the equation Kw = [H3O+][OH-]. Kw represents the ion product constant for water, which has a value of 1.0 x 10^-14 at 25°C.
Since we already know the [H3O+] concentration is 8.23 x 10^-2 M, we can rearrange the equation to solve for [OH-]. Therefore, [OH-] = Kw / [H3O+]. Substituting the values, we get:
[OH-] = (1.0 x 10^-14) / (8.23 x 10^-2)
Calculating this gives us [OH-] = 1.21 x 10^-13 M.
So, the [OH-] concentration for the solution at 25°C is approximately 1.21 x 10^-13 M.
To solve this problem, we can use the equation for the autoionization of water:
H2O ⇌ H3O+ + OH−
In water, the concentration of H3O+ (hydrogen ions) is equal to the concentration of OH− (hydroxide ions). This relationship allows us to calculate the concentration of OH− given the concentration of H3O+.
Given that [H3O+] = 8.23 × 10^−2 M, we can determine the concentration of OH− using the following equation:
Kw = [H3O+][OH−]
Where Kw is the ion product constant for water, which is equal to 1.0 × 10^−14 at 25°C.
Rearrange the equation to solve for [OH−]:
[OH−] = Kw / [H3O+]
Let's substitute the values:
[OH−] = (1.0 × 10^−14 M^2) / (8.23 × 10^−2 M)
Calculating this gives us:
[OH−] ≈ 1.21 × 10^−13 M
Therefore, the concentration of OH− in the solution at 25°C is approximately 1.21 × 10^−13 M.
To determine the [OH-] (hydroxide ion concentration) for a solution, you can use the relationship between the concentration of H3O+ ions and OH- ions in water.
In pure water at 25°C, the concentration of H3O+ ions and OH- ions are equal, and each has a concentration of 1.0 × 10-7 M. This is known as the neutral condition.
However, in this case, you are given the concentration of H3O+ ions ([H3O+] = 8.23 × 10-2 M), which means the solution is not neutral. In order to find the concentration of OH- ions, you can use the equation for Kw, which is the ion product of water, and has a constant value at a given temperature.
The equation for Kw at 25°C is:
Kw = [H3O+][OH-] = 1.0 × 10-14
Rearranging the equation to solve for [OH-]:
[OH-] = Kw / [H3O+]
Plugging in the known values:
[OH-] = (1.0 × 10-14) / (8.23 × 10-2)
Now, you can calculate the [OH-] concentration by dividing 1.0 × 10-14 by 8.23 × 10-2.