Whatis the molarity of an HCl solution if 25mL of this solution require 19.58mL of 0.1062M Sr(OH)2 solution for complete reaction? The reaction is give below

Sr(OH)2 + 2HCl --> SrCl2 + 2H2O

mols Sr(OH)2 = M x L = 0.1062 M x 0.01958 = ??

Convert mols Sr(OH)2 to mols HCl using the coefficients in the balanced equation.
mols HCl = M x L. Solve for M.

To find the molarity of the HCl solution, you can use the stoichiometry of the balanced equation and the given volume and molarity of the Sr(OH)2 solution.

First, let's find the number of moles of Sr(OH)2 (since it is given in the problem) using the equation:

moles of Sr(OH)2 = volume of Sr(OH)2 solution (in L) × molarity of Sr(OH)2 solution

Given:
Volume of Sr(OH)2 solution = 19.58 mL = 19.58/1000 L = 0.01958 L
Molarity of Sr(OH)2 solution = 0.1062 M

moles of Sr(OH)2 = 0.01958 L × 0.1062 M = 0.002077956 moles of Sr(OH)2

According to the balanced equation, the stoichiometric ratio between Sr(OH)2 and HCl is 1:2. This means that for every 1 mole of Sr(OH)2, 2 moles of HCl are required for a complete reaction.

So, the moles of HCl required would be:

moles of HCl = 2 × moles of Sr(OH)2
= 2 × 0.002077956 moles of HCl
= 0.004155912 moles of HCl

Next, let's find the volume of the HCl solution using the following formula:

volume of HCl solution (in L) = moles of HCl / molarity of HCl

We are given the volume as 25 mL, so we need to convert it to liters:

volume of HCl solution = 25 mL = 25 / 1000 L = 0.025 L

Now, we can find the molarity of the HCl solution:

molarity of HCl = moles of HCl / volume of HCl solution

molarity of HCl = 0.004155912 moles of HCl / 0.025 L

molarity of HCl = 0.166236 M

Therefore, the molarity of the HCl solution is 0.166 M.