LiOH + CO2 ----> Li2CO3 + H2O
1. how I can balance the equation?
2LiOH + CO2 ----> Li2CO3 + H2O
To balance the equation LiOH + CO2 -> Li2CO3 + H2O, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's start by counting the number of each type of atom present in the unbalanced equation:
On the left side (reactants):
Li: 1
O: 1
H: 1
C: 1
On the right side (products):
Li: 2
O: 4
H: 2
C: 1
We can observe that the number of oxygen (O) atoms on the right side is now twice as much as on the left side, and the number of hydrogen (H) atoms is also different. To balance the equation, we need to adjust the coefficients in front of each compound.
We start by adjusting the number of carbon (C) atoms by placing a coefficient of 2 in front of CO2:
LiOH + 2CO2 -> Li2CO3 + H2O
Now, there are two carbon atoms on the right side, which matches the number on the left side. However, the oxygen (O) and hydrogen (H) atoms are still unbalanced.
Next, let's balance the oxygen (O) atoms by placing a coefficient of 3 in front of H2O, which gives us:
LiOH + 2CO2 -> Li2CO3 + 3H2O
Now, we have six oxygen atoms on the right side, which matches the number on the left side. However, the hydrogen (H) atoms are still unbalanced.
Finally, let's balance the hydrogen (H) atoms by placing a coefficient of 6 in front of LiOH:
6LiOH + 2CO2 -> Li2CO3 + 3H2O
Now, we have six hydrogen atoms on both sides of the equation, which means the equation is balanced:
6LiOH + 2CO2 -> Li2CO3 + 3H2O