A 375 g sample of well water is found to contain 17.0 mg of lead. How much lead (in parts per million) is in the well water? Round to the nearest tenth. Don't forget the unit.
ok, lets go to millions...
in 375million, there ware 17(milli x million) or 17,000 grams of lead.
17,000/375,000,000 parts per million or
17/375,000 or hhhhhmmmmmm. Round to the nearest tenth? so is it 45.3 ppm ?
35.63
To calculate the concentration of lead in parts per million (ppm), we need to determine the ratio of the mass of lead to the mass of the water sample and multiply it by 1,000,000.
Step 1: Convert the mass of lead from milligrams (mg) to grams (g) to have consistent units.
17.0 mg = 17.0 × 10^-3 g
Step 2: Calculate the concentration in parts per million (ppm).
PPM = (mass of lead / mass of water sample) × 1,000,000
PPM = (17.0 × 10^-3 g / 375 g) × 1,000,000
PPM = (0.017 g / 375 g) × 1,000,000
Step 3: Simplify the expression.
PPM = 0.000045333 × 1,000,000
PPM ≈ 45.3
Therefore, the concentration of lead in the well water is approximately 45.3 parts per million (ppm).