Two charged spheres are 8.00 apart. They are moved, and the force on each of them is found to have been tripled

and the question is?

if you move them closer,

Force=3forceorighinal
kQQ/r^2=3kqq/8^2

r= 8/sqrt3 check that

To understand how the force between two charged spheres changes when their distance is altered, we can refer to Coulomb's Law. Coulomb's Law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:

F ∝ (q₁ * q₂) / r²

Where:
F is the force between the spheres,
q₁ and q₂ are the charges of the spheres, and
r is the distance between the spheres.

In this scenario, we have two charged spheres initially placed 8.00 units apart. Let's assume their charges are q₁ and q₂.

The problem states that the force on each sphere is tripled. This means the new force (F') is three times the initial force (F):
F' = 3F

If we compare the equations for the initial force and the new force, we have:
3F = (q₁ * q₂) / (8.00)²

Next, we need to determine the new distance between the spheres. Let's call it r'.
The problem doesn't specify a new distance, so we'll assume it changed uniformly.

Since the force is tripled, the initial distance must be altered accordingly. If the force increases threefold, the distance should decrease by the square root of three (approximately 1.732).

r' = 8.00 / √3

Now that we have both the new force equation and the new distance, we can calculate the charges of the spheres (q₁ and q₂) using the equations above.

Please provide any additional information if you want to calculate the specific values of the charges of the spheres or the new distance.