Algebra

I need help to solve this problem by factoring: 2x^2-x-3=0

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  1. (2x-3)(x+1)

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  2. 2x^2-x-3=0
    first step: 2*2x^-x-3=0
    4x^-x-3=0
    (4x^-4x)+(3x-3)=0
    4x(x-1)+3(x-1)
    (4x+3)(x-1)=0
    (4x+3)=0 (x-1)=0
    4x+3=0 X-1=0
    -3 -3 -1 -1
    4x=-3 x=-1
    x=-3/4
    Therefore, X=(-3/4, -1)

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