A gas occupies 8.2 liters at 2.5 atm. What is the pressure if the volume becomes 7.5 L?
Use the equation PV=nRT (pressure times volume equals moles of gas times constant times temperature). Assuming you aren't with-holding information, the number of moles of gas and the temperature must remain the same, so the initial Pressure and Volume must be equal to the final Pressure and Volume. Use this equation P1V1=P2V2. simple plug and chug.
use PV=PV Answer 2.73
To find the pressure when the volume changes from 8.2 liters to 7.5 liters, we can use the combined gas law equation. The combined gas law is given by:
(P1 * V1) / T1 = (P2 * V2) / T2
Where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
In this case, we are given the initial volume (V1 = 8.2 L) and pressure (P1 = 2.5 atm), and the final volume (V2 = 7.5 L). We need to find the final pressure (P2).
However, we are not given information about the temperature (T1 and T2) in this question. Assuming that the temperature remains constant, the equation simplifies to:
P1 * V1 = P2 * V2
Substituting the given values, we have:
(2.5 atm) * (8.2 L) = P2 * (7.5 L)
Now, solving the above equation to find P2:
(2.5 atm * 8.2 L) / 7.5 L = P2
20.5 atm = P2
Therefore, the pressure when the volume becomes 7.5 L is approximately 20.5 atm.