physics

a simple pendulum consists of a bob of mass 1.8 kg attached to a string of length 2.3 m. the pendulum is held at an angle of 30 from the vertical by a light horizontal string attached to a wall, as shown above. calculate the tension in the horizontal string. when the horizontal string is cut, calculate the speed of the bob.

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  1. pos orale... contestenla que trueno la clase :(

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  2. Chingao!

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  3. ur mom?

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  4. Incredible that in all these years nobody has answered you. I also had this problem and I got Tv*cos(30)=mg which solved out to 20.4N for the vertical tension and then to find the horizontal tension I did this, 20.4*sin(30)=10.4N, and so 10.4N is our horizontal tension.

    As for the velocity I first solved for the height difference so (y=2.3-2.3cos(30)), then Potential energy with Pe=mgh (Pe=1.8*9.8*0.3). From there I plugged the potential energy in with kinetic energy to solve for the velocity (because Pe=Ke) so that equation would be (Ke=.5MV^2), then with the values plugged in (6=.9kg*V^2). This should solve out to 2.6 m/s.

    Finally, for the period of the pendulum, our equation will look like (T=2Pi*root(L/g)) (in this case T=period, and L is of course length). Plugging in our values this equation will be something like (T=6.3*4.7) depending on how you round out which should give you a period of 2.9 seconds although again rounding will affect this a slight bit.

    Anyway, I hope you can appreciate this answer 8 years late, and as for anyone else reading in the future, I hope this helps!

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  5. its weird, bc this guy is probably like at least 27 years old LULW Weirdchamp

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