If f(x) = 2x^ - 7x +3
find f(2). I got f(2) = (-9)
find f(-3). I got f(-3) = (-42)
find f(2). I got f(2) = (-9) ... it's -7
find f(-3). I got f(-3) = (-42) ... it's 18
I think you have to recheck your signs in answer.
If f(x) = 2x^ - 7x +3
find f(2). I got f(2) = (-9)
find f(-3). I got f(-3) = (-42)
PS, if you meant 2x square root of 2, the answers would be different
f(2) = -3
f(-3) = 42
To find the value of f(x) when x is a specific number, you need to substitute that number into the function and simplify.
Given the function f(x) = 2x^2 - 7x + 3, we can find f(2) and f(-3) as follows:
1. To find f(2), substitute x = 2 into the function:
f(2) = 2(2)^2 - 7(2) + 3
= 2(4) - 14 + 3
= 8 - 14 + 3
= -6 + 3
= -3
Therefore, f(2) = -3.
2. To find f(-3), substitute x = -3 into the function:
f(-3) = 2(-3)^2 - 7(-3) + 3
= 2(9) + 21 + 3
= 18 + 21 + 3
= 42 + 3
= 45
Therefore, f(-3) = 45.
Based on your calculations, it seems that you have made an error in the calculations for f(2) and f(-3). The correct values are f(2) = -3 and f(-3) = 45.