water has a specific heat of 4184 j(kg K). How much energy is needed to increase the temperature of a kilogram of water 5 degrees celcius?
20920
To calculate the amount of energy needed to increase the temperature of water by 5 degrees Celsius, you can use the specific heat capacity formula:
Q = m * c * ΔT
where:
Q = amount of energy (in Joules)
m = mass of the water (in kilograms)
c = specific heat of water (in Joules per kilogram per Kelvin)
ΔT = change in temperature (in Kelvin)
Given:
m = 1 kg
c = 4184 J/(kg·K)
ΔT = 5 degrees Celsius
First, convert the change in temperature from Celsius to Kelvin:
ΔT = 5 K
Now, plug in the values into the formula:
Q = 1 kg * 4184 J/(kg·K) * 5 K
Simplifying the equation:
Q = 1 kg * 4184 J/(kg·K) * 5 K
= 20920 J
Therefore, the amount of energy needed to increase the temperature of 1 kilogram of water by 5 degrees Celsius is 20920 Joules.
To determine the energy needed to increase the temperature of a kilogram of water by 5 degrees Celsius, you can use the formula:
Energy = mass x specific heat x temperature change.
Here, the mass of the water is given as 1 kilogram (kg), the specific heat of water is 4184 joules per kilogram per degree Celsius (J/kg K), and the temperature change is 5 degrees Celsius (°C).
Plugging these values into the formula:
Energy = 1 kg x 4184 J/kg K x 5 °C
Energy = 20920 Joules (J)
Therefore, 20,920 Joules (J) of energy is needed to increase the temperature of a kilogram of water by 5 degrees Celsius.