Can someone check my answers please?
Solve the following by factoring?
3x^ - 6x = 0
I got x = 0 and x = 2
x = 0 only
there isn't any x = 2 since (1-2) doesn't have any variable in it, thus you cannot solve if it's all integers -> 1 - 2 = 0
Never mind I'm doing college algebra, my answers are correct.
Yeah, you're right, the answers would be x = 0 and 2 if you're equation is 3x^2 - 6x = 0
To check your answers, you can substitute the values of x back into the original equation and see if they satisfy it. Let's start by checking x = 0:
When x = 0, the equation becomes:
3(0)^2 - 6(0) = 0
0 - 0 = 0
0 = 0
So, x = 0 is indeed a solution to the equation.
Next, let's check x = 2:
When x = 2, the equation becomes:
3(2)^2 - 6(2) = 0
3(4) - 12 = 0
12 - 12 = 0
0 = 0
Again, x = 2 is a solution to the equation.
Therefore, your answers of x = 0 and x = 2 are correct as they satisfy the original equation.