If the rotational speed of each wheel is 9 revolution per second, what are the tangential speeds of a point on the rim of each wheel?
Note: Wheels spin independently with equal rotation speeds
-Diameter of Wheel A: 24
-Diameter of Wheel B: 12
9 rev/sec = 18 pi radians/sec. That is called tha angular speed, and usually has a symbol omega. Here, we often use w.
You need to provide a dimension along with the "diameter" number.
Multiply half the diameter (the radius) by the angular speed in radians per second to get the tangential speed.
Tangential speed = w*R
ok, i tried that and it's still giving me the wrong answer.
On one of the hints it says path/time. I'm so lost, haha
Tangential speed= 18pi X .24
Tangential speed= 18pi X .12
To find the tangential speed of a point on the rim of a wheel, we can use the formula:
Tangential speed = (Rotational speed) * (Circumference of the wheel)
First, let's calculate the circumference of each wheel using their diameters:
Circumference of Wheel A = π * (Diameter of Wheel A)
Circumference of Wheel B = π * (Diameter of Wheel B)
Given:
Diameter of Wheel A = 24
Diameter of Wheel B = 12
Circumference of Wheel A = π * 24
Circumference of Wheel B = π * 12
Now, we can find the tangential speeds of the points on the rims of the wheels by multiplying the rotational speed (which is 9 revolutions per second) with the respective circumference of each wheel:
Tangential speed of Wheel A = (Rotational speed of Wheel A) * (Circumference of Wheel A) = 9 * (π * 24)
Tangential speed of Wheel B = (Rotational speed of Wheel B) * (Circumference of Wheel B) = 9 * (π * 12)
Therefore, the tangential speed of a point on the rim of Wheel A is 9π * 24, and the tangential speed of a point on the rim of Wheel B is 9π * 12.