Physics

Two crewmen pull a raft through a lock, as shown in the figure . One crewman pulls with a force of 130 at an angle of 34° relative to the forward direction of the raft. The second crewman, on the opposite side of the lock, pulls at an angle of 45°. With what force should the second crewman pull so that the net force of the two crewmen is in the forward direction?

The answer must be in kN.

Below is how I worked out the problem, but it says my answer is wrong. Can someone please help?

130cos34° = 107.77
107.77/cos45° = 152.41
So, I thought .1524 kN was the answer. . .

Any suggestions? Thanks for any helpful replies!

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  1. Apparently you must use sine instead of cosine. Im still on a mission to find out why though.

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