A van accelerates down a hill (Fig. P4.71), going from rest to 30.0 m/s in 6.70 s. During the acceleration, a toy (m = 0.250 kg) hangs by a string from the van's ceiling. The acceleration is such that the string remains perpendicular to the ceiling.

Find theta

Find tension in the string

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To find the value of theta and the tension in the string, we can use the concepts of centripetal acceleration and the tension force.

Let's break down the problem:

1. First, let's find the acceleration of the van.
Given:
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 30.0 m/s
- Time (t) = 6.70 s

We can use the formula for acceleration:
a = (v - u) / t

Plugging in the given values:
a = (30.0 m/s - 0 m/s) / 6.70 s
a ≈ 4.48 m/s²

Therefore, the acceleration of the van is approximately 4.48 m/s².

2. Now, let's find the angle theta.
Since the string remains perpendicular to the ceiling, the tension force provides the necessary centripetal force to keep the toy moving in a circular path.

The centripetal force is given by:
F_c = m * a_c

Where:
- F_c is the centripetal force
- m is the mass of the toy (0.250 kg in this case)
- a_c is the centripetal acceleration

Since the tension in the string provides the centripetal force, we can write:
T = F_c

To find the centripetal acceleration, we can use the formula:
a_c = r * ω²

Where:
- r is the radius of the circular path
- ω is the angular velocity (which is determined by the hanging angle theta)

Given that the string remains perpendicular to the ceiling, the circular path radius is equal to the length of the string. So, let's say L is the length of the string.

Plugging in the known values, we have:
a_c = L * ω²

3. Now, let's find the tension in the string.
We can write Newton's second law equation for the vertical motion of the toy:
Sum of forces in the y-direction = m * a_y

Considering only the tension force and gravitational force, we can write:
T - m * g = m * a_y

Since the toy is hanging at rest, the vertical acceleration is zero, i.e. a_y = 0. Therefore,
T - m * g = 0

Solving for T, we get:
T = m * g

Now, let's summarize the findings:

- The acceleration of the van: 4.48 m/s²
- The circular path radius (string length): L
- The tension in the string: T = m * g
- The angle theta (which determines the angular velocity, ω): To be determined using the centripetal acceleration formula a_c = r * ω²

To find the angle theta, we need more information, such as the length of the string (L) or any other related measurements.