16y^2 - 4y + 1 = 0
I'm trying to find the roots for the equation. What do I do next after this step:
4y (4y - 1) + 1 = 0
It's impossible to solve that equation
After the step you provided, which is factoring out the common factor of 4y, the next step is to simplify the expression.
Let's break it down:
4y(4y - 1) + 1 = 0
Expanding the expression within the parentheses:
16y^2 - 4y + 1 + 1 = 0
Combining like terms:
16y^2 - 4y + 2 = 0
Now, the equation is in the form of a quadratic equation, which is a standard form equation: ax^2 + bx + c = 0, where a, b, and c are coefficients.
To find the roots of this quadratic equation, you can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, the coefficients are:
a = 16
b = -4
c = 2
Now, you can substitute these values into the quadratic formula and solve for y.