3x^2 - x - 4

Qadratic equation;

y=ax^2+bx+c

In your case:

a=3 b=-1 c=-4

Discriminant: D=b^2-4ac

D=(-1)^-4*3*(-4)

D=1+48

D=49

When D>0 equation hawe two real solutions.

x1=[-b-sqroot(b^2-4ac)]/2a

x1=[-(-1)-sqroot(49)]/(2*3)

x1=(1-7)/6

x1= -6/6

x1= -1

x2=[-b+sqroot(b^2-4ac)]/2a

x2=[-(-1)+sqroot(49)]/(2*3)

x2=(1+7)/6

x2=8/6

x2=(2*4)/(2*3)

x2=4/3

x2=1.333333

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