Please help!
Suppose that a 400 gram copper object (specific heat 0.092 cal/g/degrees Celsius) receives 900 cal. of heat. What is the temperature change? Explain your reasoning. Do not use algebra
Thanks!
900cal=400grams*.092cal/C*delatTemp
solve for DeltaTemp.
Do not use algebra? You have to be kidding. You could estimate it, 400x.1=40, and 400/40 is about 10C.
oops, the danger of estimated in the head.
900/40 is about 23C
Use algebra, and a calculator.
To find the temperature change of the copper object, we need to use the specific heat formula:
Q = m * c * ΔT
Where:
Q = amount of heat received
m = mass of the object
c = specific heat of the material
ΔT = change in temperature
In this case, we know the mass of the copper object (400 grams) and the amount of heat received (900 cal). We also know the specific heat of copper (0.092 cal/g/degrees Celsius).
We can rearrange the formula to solve for ΔT:
ΔT = Q / (m * c)
Substituting the given values:
ΔT = 900 cal / (400 g * 0.092 cal/g/degrees Celsius)
To simplify the calculation, we divide 900 cal by 400 g first:
ΔT = 2.25 cal/g / 0.092 cal/g/degrees Celsius
Now, we can cancel out the "cal/g" units:
ΔT = 2.25 / 0.092 degrees Celsius
Finally, by dividing 2.25 by 0.092, we find:
ΔT ≈ 24.46 degrees Celsius
Therefore, the temperature change of the copper object is approximately 24.46 degrees Celsius.
Note: It's important to keep units consistent throughout the calculation to ensure an accurate result.