a) What is the minimum work needed to push a 900 kg car 410 m up a 17.5° incline with zero friction?

If i know this answer is 1.08e6 what equation should i use for the next part because the one i used was wrong

(b) What is the minimum work needed if the effective coefficient of friction is 0.40?

(b) W = M g H + friction work

= M g X sin17.5 + M g X cos 17.5 * 0.4

X = 410 m

To find the minimum work needed to push the car up the incline, we can use the work-energy principle. The work done on an object is equal to the change in its potential energy.

For part (a), where there is zero friction, we can calculate the work done against gravity. The equation for the work done against gravity is:

Work = Force x Distance x cos(θ)

Where:
- Force is the component of the force parallel to the displacement, which is equal to the weight of the car (mass x gravity)
- Distance is the displacement along the incline
- θ is the angle of the incline

Using this equation, the minimum work needed can be calculated by substituting the given values into the formula:

Work = (Force x Distance x cos(θ))

Given:
- Mass of the car (m) = 900 kg
- Distance (d) = 410 m
- Incline angle (θ) = 17.5°

First, calculate the force:

Force = Weight = mass x gravity

Since gravity is approximately 9.8 m/s^2:

Force = 900 kg x 9.8 m/s^2

Next, calculate the work:

Work = (Force x Distance x cos(θ))

Substitute the values:

Work = (900 kg x 9.8 m/s^2 x 410 m x cos(17.5°))

After calculating this expression, you should get the answer as 1.08e6 J (representing 1.08 x 10^6 Joules).

For part (b), where there is an effective coefficient of friction, we need to consider the additional work done against friction. The equation for the work done against friction is:

Work_friction = Force_friction x Distance

Where:
- Force_friction is the component of the force due to friction, which is equal to the coefficient of friction multiplied by the normal force (mass x gravity x cos(θ))
- Distance is the displacement along the incline

The total work done in this case would be the sum of the work done against gravity and the work done against friction:

Total work = Work_gravity + Work_friction

Substitute the given values and calculate accordingly to find the minimum work needed.