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Find the functional values f(-2), f(0), and f(1) for the function. ƒ(x) = x² - 1
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Find the functional values f(-2), f(0), and f(1) for the function. ƒ(x) = X²- 1
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To find the functional values f(-2), f(0), and f(1) for the function ƒ(x) = x² - 1, you simply
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Find the functional values f(-2), f(0), and f(1) for the function. ƒ(x) = x² - 1
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f(-2)= (-2)^2 - 1 = 3 Can you do the rest?
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#1 Extrema occur where the derivative is zero f(x)= (3/4)x^4 - x^3 - 3x^2 +6x f'(x) = 3x^3 - 3x^2 -
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y = 5/4x^4 + 2/3x^3 - 5x^2 - 4x + 5 y' = 5x^3 + 2x^2 - 10x - 4 = (5x+2)(x^2-2) y" = 15x^2 + 4x - 10
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