Find, to the nearest tenth of a centimeter, the length of a diagonal of a square if the measure of one side is 8.0 centimeters.
See this post. Only the side length is different. Same method is used.
http://www.jiskha.com/display.cgi?id=1298927532
reouignerg
find to the nearest tenth of a centimeter the length of a diagonal of a square if the measure of one side is 8.0 centimeters
To find the length of the diagonal of a square, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In the case of a square, all sides are equal, so each side has a length of 8.0 centimeters. Let's call the length of the diagonal "d".
Applying the Pythagorean theorem, we have:
d^2 = (8.0 cm)^2 + (8.0 cm)^2
Simplifying the equation:
d^2 = 64 cm^2 + 64 cm^2
d^2 = 128 cm^2
Now, we can find the value of "d" by taking the square root of both sides:
d ≈ √(128 cm^2)
d ≈ 11.3 cm
Therefore, the length of the diagonal of the square, to the nearest tenth of a centimeter, is approximately 11.3 centimeters.