# Algebra 1

Question:
The height in feet above the ground of an arrow t seconds after it is shot can be modeled by y = -16t(squared) + 63t + 4. Can the arrow pass over a tree that is 68 feet tall? Explain.

Completely lost, could anyone help me out?

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1. y = height = -16t^2 + 63t + 4
The vertex of this parabola is called the maximum point.

Vertex = -b/2a
Vertex = -63/(2(-16))
Vertex = t value = 1.96875

So, the maximum value for t seconds is 1.96875

y = height = -16t^2 + 63t + 4
t = 1.96875
y = -16(1.96875)^2 + 63(1.96875) + 4
y = -16(3.875977) + 124.0313 + 4
y = 66.0157

So, the maximum height = 66.0157 feet

Use could also use derivatives to find the maximum value for t.

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posted by Helper
2. Thank you so much, this really helped! :)

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posted by Kai
3. You're welcome :)

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posted by Helper
4. dont do it

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5. Thank you sooooo much. Literally been working on this for over an hour. LIFE SAVERRR

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posted by Kiara

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