If A and B are independent events, P(A) = 0.35, and P(B) = 0.55, find the probabilities
a) P(A intersected B)
b) P(A united B)
P(A and B) = (.35)(.55) = .1925
P(A OR B) = .35 + .55 - .1925
To find the probabilities of A intersected B and A union B, we can use the formulas for independent events.
a) P(A intersected B) = P(A) * P(B)
Since A and B are independent events, the probability of both A and B happening is equal to the product of their individual probabilities.
P(A intersected B) = 0.35 * 0.55 = 0.1925
b) P(A united B) = P(A) + P(B) - P(A intersected B)
The probability of A union B is the sum of the individual probabilities of A and B minus the probability of their intersection.
P(A united B) = 0.35 + 0.55 - 0.1925 = 0.7075