Solve the triangle
a is a side A is an angle
I have:
a=5 A=
b=11 B=
c= C= 110 degrees
Can this be figured out??If so how?
by Cosine Law
c^2 = 11^2+5^2 - 2(11)(5)cos110º
=183.622
c= 13.55
Now you can use the Sine Law to find the other angles
Thank you , I was forgetting to multiply by cos 110
Yes, this triangle can be solved using the given information. To solve the triangle, we can use the Law of Sines or the Law of Cosines, depending on which information we have available.
In this case, we have the length of side a (a = 5) and the measure of angle A (A = ?). We also have the length of side b (b = 11) and the measure of angle C (C = 110 degrees).
Using the Law of Sines, we can write the ratio of the length of a side to the sine of its corresponding angle for all three sides of the triangle:
a/sin(A) = b/sin(B) = c/sin(C)
Since we have the values of a, b, and C, we can rearrange the formula to solve for angle C:
sin(C) = (c * sin(A)) / a
sin(110 degrees) = (c * sin(A)) / 5
Now, let's calculate sin(110 degrees):
sin(110 degrees) ≈ 0.9397
Substituting the given values into the equation, we can solve for the length of side c:
0.9397 = (c * sin(A)) / 5
We need the measure of angle A in order to solve for c. However, the information for angle A is not provided, so we cannot determine the exact value of side c.
Therefore, to fully solve the triangle, we need the measure of angle A. Without it, we cannot determine the length of side c.