A balanced equation for CuSO4+NaCl--> ???
no reaction.
1. There is no precipitate (all of the possible combinations for products are soluble).
2. None of the possible products are gases.
3. None of the possible products are weak electrolytes; i.e., not 100% ionized.
4. No oxidation-reductions are going on
ergo: no reaction.
To balance the equation CuSO4 + NaCl, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
First, let's break down the given compounds into their constituent elements:
CuSO4 ➝ Cu + S + O4
NaCl ➝ Na + Cl
Now, let's write the balanced equation step by step:
1. Start with the unbalanced equation:
CuSO4 + NaCl ➝ Cu + S + O4 + Na + Cl
2. Count the number of atoms for each element on both sides of the equation.
On the left side:
- Cu: 1
- S: 1
- O: 4
- Na: 1
- Cl: 1
On the right side:
- Cu: 1
- S: 1
- O: 4
- Na: 1
- Cl: 1
3. Balance each element separately:
Copper (Cu):
There is already one Cu atom on both sides of the equation, so it is balanced.
Sulfur (S):
There is already one S atom on both sides of the equation, so it is also balanced.
Oxygen (O):
On the left side, we have 4 oxygen (O) atoms, and on the right side, we have none. To balance oxygen, we can add 4 oxygen atoms on the right side:
CuSO4 + NaCl ➝ Cu + S + O4 + Na + Cl
Sodium (Na):
There is already one Na atom on both sides of the equation, so it is balanced.
Chlorine (Cl):
There is already one Cl atom on both sides of the equation, so it is also balanced.
The final balanced equation is:
CuSO4 + 4NaCl ➝ Cu + S + 4Na + O4 + Cl
It's important to note that the balanced equation may not always be unique. There can be multiple correct balanced equations depending on the condition and context of the chemical reaction.