What is the molar concentration of Na+ in a solution prepared by dissolving 100.0g of Na3PO4 in sufficient H20 to form 2.00L of solution??
To find the molar concentration of Na+ in the solution, you need to determine the number of moles of Na+ and then divide it by the volume of the solution.
First, you need to calculate the number of moles of Na3PO4 in the solution. The molar mass of Na3PO4 can be calculated by adding the atomic masses of sodium (Na), phosphorus (P), and oxygen (O). The atomic masses are:
Na: 22.99 g/mol
P: 30.97 g/mol
O: 16.00 g/mol
Na3PO4 has three sodium atoms, one phosphorus atom, and four oxygen atoms, so the molar mass is:
3 * 22.99 + 30.97 + 4 * 16.00 = 163.99 g/mol
Next, calculate the number of moles of Na3PO4 by dividing the given mass by the molar mass:
moles of Na3PO4 = mass of Na3PO4 / molar mass of Na3PO4
= 100.0 g / 163.99 g/mol
Now, you need to find the number of moles of Na+ in Na3PO4. Each mole of Na3PO4 contains three moles of Na+, so:
moles of Na+ = moles of Na3PO4 * 3
Finally, divide the number of moles of Na+ by the volume of the solution in liters to get the molar concentration:
molar concentration of Na+ = moles of Na+ / volume of solution
Given that the volume of the solution is 2.00 L, you can substitute the values into the equation to find the molar concentration of Na+.