How many grams of MgCl2 are required to make 350mL of a 0.56M solution of MgCl2?
How many moles do you want? moles = M x L = 0.350*0.56 = ??
moles = grams/molar mass
Solve for grams.
To calculate the number of grams of MgCl2 required to make a certain concentration (molarity) solution, you need to use the formula:
moles = concentration × volume
1. First, convert the given volume from milliliters (mL) to liters (L):
350 mL = 350 ÷ 1000 = 0.35 L
2. Now, rearrange the formula:
moles = concentration × volume
to solve for moles:
moles = 0.56 M × 0.35 L
3. Calculate the number of moles by multiplying the given concentration (0.56 M) by the volume (0.35 L):
moles = 0.56 × 0.35 = 0.196 moles
4. The molar mass of MgCl2 can be obtained from the periodic table:
Mg = 24.31 g/mol
Cl = 35.45 g/mol × 2 (since there are two chlorine atoms in MgCl2)
Molar mass of MgCl2 = 24.31 g/mol + (35.45 g/mol × 2) = 95.31 g/mol
5. Now, you can calculate the number of grams by multiplying the number of moles by the molar mass:
grams = moles × molar mass
grams = 0.196 moles × 95.31 g/mol = 18.67 grams
Therefore, you would need approximately 18.67 grams of MgCl2 to make a 350 mL 0.56 M solution of MgCl2.