Okay I only need help with part (c), but I'll put down the whole problem.
a. What impulse occurs when an average force of 10 N is exerted on a cart for 2.5 s? I got 25 N x S (Newtons-Seconds)
b. What change in momentum does the cart undergo? I got 25 kg x m/s.
c. If the mass of the cart is 2 kg and the cart is initially at rest, calculate its final speed.
This sheet I have says the answer to part (c) is 12.5 m/s, but I have NO CLUE how to get that answer. Plz help!!!
momentum = mass * velocity
velocity = momentum/mass
v = 25/2 = 12.5
(you can fill in the units)
Thank you very much! I get it now!
how do you fingure out the rest of the questions?
To solve part (c) of the problem, we can use the equation that relates impulse and change in momentum to find the final velocity.
Impulse is defined as the product of average force and time, which is given as 25 N·s in part (a). We can also use the formula for impulse:
Impulse = Change in momentum
Since impulse and change in momentum are equal, the change in momentum of the cart is also 25 N·s.
The change in momentum is given by the formula:
Change in momentum = mass × final velocity
Rearranging the equation, we can solve for the final velocity:
Final velocity = Change in momentum / mass
Plugging in the values we know:
Final velocity = 25 N·s / 2 kg
Simplifying the expression:
Final velocity = 12.5 m/s
Therefore, the final speed of the cart is 12.5 m/s.