Hello,

what is the absolute value of ((3x-2)^2) ? I know normally, if this was 3x-2, you would do -1<3x-2<1 and isolate x to find the range , but what do you do since there's the "squared" ??

thanks!

What do you have if you squared a value or a number? You'll get a positive number the whole time. Except for 0, of course. In this case, the range will be at least 0, or >=0, regardless of the value of x