Hello,
what is the absolute value of ((3x-2)^2) ? I know normally, if this was 3x-2, you would do -1<3x-2<1 and isolate x to find the range , but what do you do since there's the "squared" ??
thanks!
what is the absolute value of ((3x-2)^2) ? I know normally, if this was 3x-2, you would do -1<3x-2<1 and isolate x to find the range , but what do you do since there's the "squared" ??
thanks!