A rectangular sheet of
aluminum foil is 50 centimeters long and 20 centimeters
wide, and weighs 5.4 grams. Find the thickness
of the aluminum foil in centimeters.
D = kg/V = 2700kg/m^3.
5.4*10^-3 / V = 2700,
V = 5.4*10^-3 / 2.7*10^3 = 2*10^-6.
V = 0.05 * 0.02 * T = 2*10^-6,
1*10^-3*T = 2*10^-6,
T = 2*10^-6 / 1*10^-3 = 2*10^-3m = 2mm.
To find the thickness of the aluminum foil, you can use the formula:
thickness = (weight) / (length * width)
In this case, the weight of the aluminum foil is 5.4 grams, the length is 50 centimeters, and the width is 20 centimeters.
Substituting these values into the formula, we get:
thickness = 5.4 grams / (50 centimeters * 20 centimeters)
To simplify the calculation, we convert grams to centimeters by dividing by the density of aluminum, which is 2.7 grams per cubic centimeter.
thickness = (5.4 grams / 2.7 grams per cubic centimeter) / (50 centimeters * 20 centimeters)
Calculating the numerator, we have:
5.4 grams / 2.7 grams per cubic centimeter = 2 cubic centimeters
Substituting this value back into the formula:
thickness = 2 cubic centimeters / (50 centimeters * 20 centimeters)
Now, we perform the multiplication in the denominator:
thickness = 2 cubic centimeters / (1000 square centimeters)
Simplifying the fraction, we find:
thickness = 0.002 centimeters
Therefore, the thickness of the aluminum foil is 0.002 centimeters or 0.02 millimeters.