Copper (II) fluoride contains 37.42%by mass. Calculate the mass of fluorine(in grams)contained in 55.5 g of Copper(II) Fluoride.
37.43% by mass of WHAT?????. But you really don't need to do that.
Just use dimensional analysis and convert 55.5 g Cu(II) fluoride to fluorine.
55.5 g CuF2 x (2 moles F/1 mole CuF2) =??
Use atomic mass*2 for F and use molar mas for CuF2.
Copper (II) fluoride contains 37.42% F by mass. Use this percentage to calculate the mass of fluorine in grams contained in 24.0 g of copper (II) fluoride.
111F
15.0
To calculate the mass of fluorine in copper (II) fluoride, we need to use the percentage composition of fluorine in the compound.
Step 1: Find the molar mass of Copper (II) Fluoride (CuF2)
To do this, we need to know the atomic masses of copper (Cu) and fluorine (F).
The atomic mass of copper (Cu) is 63.55 g/mol.
The atomic mass of fluorine (F) is 18.998 g/mol.
Since Copper (II) Fluoride contains 2 fluorine atoms, we can calculate the molar mass as follows:
Molar mass of CuF2 = (1 x Atomic mass of Cu) + (2 x Atomic mass of F)
= (1 x 63.55 g/mol) + (2 x 18.998 g/mol)
= 63.55 g/mol + 37.996 g/mol
= 101.546 g/mol
So, the molar mass of Copper (II) Fluoride is 101.546 g/mol.
Step 2: Calculate the mass of fluorine in 1 mole of Copper (II) Fluoride
Since fluorine makes up 37.42% of the compound, we can calculate the mass of fluorine in 1 mole of Copper (II) Fluoride as follows:
Mass of fluorine in 1 mole of CuF2 = 37.42% x Molar mass of CuF2
= 0.3742 x 101.546 g/mol
= 37.96 g
Therefore, 1 mole of Copper (II) Fluoride contains 37.96 grams of fluorine.
Step 3: Calculate the amount of Copper (II) Fluoride using the given mass
Now that we know that 1 mole of Copper (II) Fluoride contains 37.96 grams of fluorine, we can calculate the number of moles of Copper (II) Fluoride in the given mass of 55.5 grams:
Number of moles of CuF2 = Mass of CuF2 / Molar mass of CuF2
= 55.5 g / 101.546 g/mol
= 0.546 mol
Step 4: Calculate the mass of fluorine in the given mass of Copper (II) Fluoride
Finally, we can calculate the mass of fluorine in 55.5 grams of Copper (II) Fluoride by multiplying the number of moles of Copper (II) Fluoride by the mass of fluorine in 1 mole:
Mass of fluorine = Number of moles of CuF2 x Mass of fluorine in 1 mole of CuF2
= 0.546 mol x 37.96 g/mol
= 20.71 g
Therefore, the mass of fluorine in 55.5 grams of Copper (II) Fluoride is 20.71 grams.