Login or Sign Up

Ask a New Question

Insert 3 numbers between15 to 17 such that the terms from an Arithmetic progression

let the sequence be

15 , 15+d, 15+2d, 15+3d, and 17

then 17 - (15+3d) = d
17 - 15 - 3d = d
-4d = -2
d = 1/2 or .5

the inserted numbers are 15.5, 16, and 16.5

Similar Questions

Three numbers are in an arithmetic progression; three other numbers are in a ge- ometric progression. Adding the corresponding

Top answer: The AP numbers are: a, a+d, a+2d The GP numbers are: b, br, br^2 Add the terms, and you get a+b = 32 Read more.
The first, the third and the seventh terms of an increasing arithmetic progression are three consecutive terms of a geometric

Top answer: AP: 10,10+2d,10+6d GP: (10+2d)/10 = (10+6d)/(10+2d) d = 5 check: AP: 10,15,20,25,30,35,40 GP: Read more.
if 1, 2, 7 and 20, respectively, are added to the first terms of an arithmetic progression, a geometric progression of four

Top answer: let the first 4 terms of the AP be a-d, a , a+d, and a+2d new sequence is a-d+1, a+2, a+d + 7, and Read more.
The sum of three different numbers which are consecutive terms of a geometric progression is 28. The numbers are also the first,

Top answer: Use your definitions. a + ar + ar^2 = 28 a(1+r+r^2) = 28 for the AP information: the first terms Read more.
The numbers p,10 and q are 3 consecutive terms of an arithmetic progression .the numbers p,6 and q are 3 consecutive terms of a

Top answer: from the first: 10-p = q-10 q = 20-p from the second: pq = 36 by substitution, p(20-p) = 36 20p - Read more.
The first three terms of an arithmetic progression are 1/2, x, 25. The first three terms of a geometric progression are x+1/4,

Top answer: (25 - 1/2)/2 = 49/4 so, x = 49/4 (32 1/2)/(50/4) = y/(32 1/2) y = 169/2 Read more.
The first,third and seventh term of an arithmetic progression form three consecutive terms of a geometric progression. If the

Top answer: If your sentence means: If the first of the arithmetic progression is 6. then In A.P. an = a1 + ( n Read more.
Two arithmetic progression have thd same first and last terms.the first arithmetic progression has 21 terms with a common

Top answer: 46 Read more.
The first and last terms of an arithmetic progression are 7and -33 respecctively. Find the number of terms in the arithmetic

Top answer: -33-7 = -40 -40/-10 = 4 now finish it off Read more.
The sum of the 3 terms in arithmetic sequence is 39.if these numbers is increased by 1,5 and 12 respectively the numbers would

Top answer: 3/2 (2a+2d) = 39 (a+d+5)/(a+1) = (a+2d+12)/(a+d+5) a=11, d=2 AP: 11,13,15 GP: 12,18,27 a=26, d= -13 Read more.