proof that x^0 = 1
x5
------------- =
X5
x*x*x*x*x
----------- = 1 =
x*x*x*x*x
x5-5 = x0 = 1
To prove that x^0 = 1, we can use the fact that any number divided by itself is equal to 1.
Let's consider x raised to the power of 5, denoted as x^5.
We can write x^5 as x * x * x * x * x.
Now, if we divide x^5 by x^5, we get:
(x * x * x * x * x) / (x * x * x * x * x).
According to the properties of division, when we divide two numbers with the same base, we subtract the exponents.
So, we can rewrite this as:
x^(5-5).
When we subtract 5 from 5, we get 0.
Therefore, we have:
x^0 = 1.
Hence, we have proven that x^0 is equal to 1.