What is the force between two small charged spheres that have charges of 2 x 10^-7 and 3 x 10^-7 if the distance of r is 30 cm.

I think you use Force = the constant of K multiplied by the product of the charges divided by the square of the distance again. If you plug in the numbers, you would get 6 x 10^-7.

I am almost sure this is right, if you could please plug in the numbers and let me know if this is the answer because for some reason I can never get the right numbers even if I follow the right steps.

Please let me know if this is right.
As always, your help is very much appreciated.

=)

Thanks!
I once heard that those who help others, help themselves (its from the Bible) and that is so true!

You are correct. I will gladly critique your calculations.

actually, i think you have to convert cm to m. therefore, you would get 6 x 10^-2 as an answer

Gaga

To calculate the force between two charged spheres, you are correct that you can use the formula:

Force = K * (q1 * q2) / r^2

Where:
- Force is the magnitude of the force between the charges,
- K is the electrostatic constant, which has a value of 9 x 10^9 Nm^2/C^2,
- q1 and q2 are the charges of the spheres, and
- r is the distance between the centers of the spheres.

In this case, you have the charges q1 = 2 x 10^-7 C and q2 = 3 x 10^-7 C, while the distance r is given as 30 cm, or 0.3 m.

Plugging in these values into the formula, you get:

Force = (9 x 10^9 Nm^2/C^2) * ((2 x 10^-7 C) * (3 x 10^-7 C)) / (0.3 m)^2

To simplify the calculation, let's perform the multiplication and exponentiation steps separately:

Force = (9 x 10^9 Nm^2/C^2) * (6 x 10^-14 C^2) / (0.09 m^2)

Now, let's multiply the numbers outside the parentheses:

Force = 54 x 10^-5 Nm^2 / (0.09 m^2)

Next, let's divide the numerator by the denominator:

Force = 6 x 10^-4 N

So, the force between the two charged spheres is 6 x 10^-4 N.

Your initial answer of 6 x 10^-7 N is incorrect due to a calculation mistake. The right answer is 6 x 10^-4 N.

Remember to double-check your calculations to ensure accuracy.