ok, so i have to find the mass of the HNO3 in 1 L and the mass of the H2O in 1 L.
I'm given:
HNO3 solution
1.42 g/mL
16M
I'm really terrible at this stuff and it should be easy, but I have no idea where to start.
16 M means 16 mols HNO3/L of solution.
How much is 16 moles HNO3? 1 mole = approximately 63 grams (1+14+48=about 63) so 16 moles would be 16 x 63 grams in 1 L.
How much does 1 L of the solution weigh? It has a density of 1.43 g/mL; therefore, 1000 mL is
1000 x 1.42 g/mL = 1420 grams.
How much of that is HNO3. From above.
Then mass water = 1420 g - mass HNO3.
ok, sweet. i had most of that set up right.
so the mass of HNO3 = 1008 g & the mass of H2O = 412 g?
To find the mass of HNO3 in 1 L and the mass of H2O in 1 L, there are a few steps you can follow:
Step 1: Understand the given information:
- Density of the HNO3 solution: 1.42 g/mL
- Concentration of the HNO3 solution: 16 M (moles per liter)
Step 2: Start with the mass of HNO3:
- To find the mass, first, calculate the number of moles of HNO3 in 1 L of the solution using the concentration.
- The molar mass of HNO3 can be calculated by adding up the atomic masses of the elements: H (1 g/mol) + N (14 g/mol) + O (16 g/mol) = 63 g/mol.
- Multiply the molar mass of HNO3 by the concentration in moles per liter to get the mass of HNO3 in grams.
Step 3: Calculate the volume of HNO3 in 1 L:
- To find the volume of HNO3, divide the mass of HNO3 by its density (g/mL). This will convert grams to milliliters.
Step 4: Calculate the mass of H2O in 1 L:
- Since the total volume of the solution is 1 L, subtract the volume of HNO3 from the total volume to get the volume of H2O.
- Multiply the volume of H2O by the density to get the mass in grams.
Let's do the calculations step by step:
Step 1: Molar mass of HNO3 = 63 g/mol
Step 2: Moles of HNO3 = Concentration * Volume (in liters)
= 16 mol/L * 1 L
= 16 mol
Mass of HNO3 = Moles * Molar mass
= 16 mol * 63 g/mol
= 1008 g
Step 3: Volume of HNO3 = Mass of HNO3 / Density
= 1008 g / 1.42 g/mL
= 709.86 mL
Step 4: Volume of H2O = Total volume - Volume of HNO3
= 1000 mL - 709.86 mL
= 290.14 mL
Mass of H2O = Volume of H2O * Density
= 290.14 mL * 1.00 g/mL
= 290.14 g
So, the mass of HNO3 in 1 L of the solution is approximately 1008 grams, and the mass of H2O in 1 L of the solution is approximately 290.14 grams.