f(x)=12x/sinx+cosx
find f'(-pie)
anybody know the answer!!!
Please type your subject in the School Subject box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.
clarify if you mean
f(x) = 12x/(sinx + cosx) or the way you typed it.
f(x)= 12x
________
sinx+cosx
thats how the problem is and i need to find f'(-pie)
From your previous post, which MathMate answered.
f(x) = 12x/(sinx + cosx)
for -pi
calculus-correction - MathMate, Thursday, February 24, 2011 at 9:45pm
The required problem was
f(-π)
= 12(-π)/(0+(-1))
= 12π
12pi is the answer.
You have said that this is not the answer.
Please post what you think the answer is then.
I checked this with an online calculator and got the same answer as MathMate.
FYI, In the future it would help if you used parenthesis as MathMate and Reiny requested.
Like this,
f(x) = 12x/(sinx + cosx)
sorry about that and i said yes that was the way but in the computer it doesnt have the parenthesis but yeah its the same way that the problem im trying to solve
im confused on this problem and i really need some help if you can help me and yes that is the problem i am trying to solve i would appreciate it
To find the derivative of the function f(x) = 12x/sin(x) + cos(x), and then evaluate it at x = -π, we can follow these steps:
Step 1: Find the derivative of the function f(x) with respect to x.
To do this, you can apply the quotient rule, which states that if you have a function in the form u(x)/v(x), then its derivative is given by:
f'(x) = (v(x) * u'(x) - u(x) * v'(x))/[v(x)]^2
For our function f(x) = 12x/sin(x) + cos(x), let's define u(x) = 12x and v(x) = sin(x). We also need to find their derivatives:
u'(x) = 12
v'(x) = cos(x)
Using the quotient rule, we substitute these values into the formula:
f'(x) = [sin(x) * 12 - 12x * cos(x)] / [sin(x)]^2
Step 2: Evaluate the derivative function at x = -π.
To find f'(-π), we simply substitute x = -π into the derivative expression we obtained in step 1:
f'(-π) = [sin(-π) * 12 - 12(-π) * cos(-π)] / [sin(-π)]^2
Step 3: Simplify the expression.
Now, we can evaluate the sine and cosine of -π:
sin(-π) = 0
cos(-π) = -1
Using these values, we simplify the expression:
f'(-π) = [0 * 12 - 12(-π) * (-1)] / [0]^2
= [12π] / 0
Note that we cannot divide by zero. Therefore, this expression is undefined.
Hence, the derivative of f(x) at x = -π is undefined.