2NaHCO3(s)+ heat -->Na2CO3(s)+ H2O(g)+CO2(g) is this right ?
Determine how many moles of CO2(g) is
produced when 7mols of NaHCO3 are consumed. question i asked earlier, i got 3.5 moles am i right ?
I answered your question the first time you posted.
How did you get 14 below and 3.5 for this post and both are the same question?
To determine how many moles of CO2(g) are produced when 7 moles of NaHCO3 are consumed, we can use the balanced chemical equation:
2NaHCO3(s) + heat → Na2CO3(s) + H2O(g) + CO2(g)
From the balanced equation, we can see that for every 2 moles of NaHCO3 consumed, 1 mole of CO2 is produced. This means that the ratio of NaHCO3 to CO2 is 2:1.
So, if you have 7 moles of NaHCO3, you can calculate the number of moles of CO2 produced by dividing 7 moles by the ratio:
7 moles NaHCO3 × (1 mole CO2 / 2 moles NaHCO3) = 3.5 moles CO2
Therefore, you are correct. When 7 moles of NaHCO3 are consumed, 3.5 moles of CO2 are produced.