A bag contains 3 red marbles, 5 yellow marbles and 6 orange marbles. Three marbles are drawn and NOT replaced each time. Determine the probability of drawing three yellow marbles in a row.

(5/14)(4/13)(3/12)

= .....

551 To determine the probability of drawing three yellow marbles in a row, we need to use the concept of probability.

Step 1: Calculate the total number of marbles in the bag.
In this case, the total number of marbles in the bag is 3 + 5 + 6 = 14.

Step 2: Calculate the probability of drawing a yellow marble on the first draw.
There are 5 yellow marbles out of a total of 14 marbles, so the probability of drawing a yellow marble on the first draw is 5/14.

Step 3: Calculate the probability of drawing a yellow marble on the second draw.
After drawing one marble without replacement, there will be a total of 13 marbles left in the bag. Since one yellow marble has already been drawn, there will be 4 yellow marbles left out of the remaining 13 marbles. Therefore, the probability of drawing a yellow marble on the second draw is 4/13.

Step 4: Calculate the probability of drawing a yellow marble on the third draw.
After drawing two marbles without replacement, there will be a total of 12 marbles left in the bag. Since two yellow marbles have already been drawn, there will be 3 yellow marbles left out of the remaining 12 marbles. Therefore, the probability of drawing a yellow marble on the third draw is 3/12.

Step 5: Calculate the overall probability of drawing three yellow marbles in a row.
To find the overall probability, we multiply the probabilities of each independent event. Therefore, the probability of drawing three yellow marbles in a row is (5/14) x (4/13) x (3/12) = 60/3276.

Simplifying the fraction, we get the final probability as 5/273.