a catalytic converter combines 2.25 g CO with excess O2 What mass of Co2 is formed
Here is an example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the mass of CO2 formed, we need to first understand the balanced chemical equation for the combustion of CO with O2. The balanced equation is:
2 CO + O2 -> 2 CO2
From the balanced equation, we can see that 2 moles of CO react with 1 mole of O2 to produce 2 moles of CO2. Now let's calculate the number of moles of CO:
Mass of CO = 2.25 g
Molar mass of CO = 12 g/mol + 16 g/mol = 28 g/mol
Number of moles of CO = Mass of CO / Molar mass of CO
Number of moles of CO = 2.25 g / 28 g/mol ≈ 0.0804 mol
Since the reaction ratio is 2:2, the number of moles of CO2 formed will be the same as CO. Therefore, 0.0804 mol of CO2 is formed.
To calculate the mass of CO2 formed, we need to know the molar mass of CO2:
Molar mass of CO2 = 12 g/mol + (2 * 16 g/mol) = 44 g/mol
Mass of CO2 formed = Number of moles of CO2 * Molar mass of CO2
Mass of CO2 formed = 0.0804 mol * 44 g/mol ≈ 3.54 g
Therefore, approximately 3.54 grams of CO2 is formed.