f(x)=12x/sinx+cosx

find f(-pie)

Parentheses are required. As it is, it will be interpreted as:

f(x)=(12x/sin(x))+cos(x)

For f(x)=12x/(sin(x)+cos(x))
f(π)
= 12π/(sin(π)+cos(π)
= 12π/(0+(-1))
= -12π

the computer says its not the answer incorrect it says

The required problem was

f(-π)
= 12(-π)/(0+(-1))
= 12π

Sorry for the oversight. Hope you still have "lives" left.

Do check my answer and agree with it before going to the computer!

i have unlimited trys so it don't matter but 12pi not the answer either

Have you checked my assumptions?

I worked with
f(x)=12x/(sinx+cosx)
and not
f(x)= (12x/sinx) + cosx
as you posted.

Check also if there is any typo on the question.

If everything is correct, then
f(-π)=12π, since sin(-π)=0, cos(-π)=-1.

Check also how you entered π in your answer. Do not enter 3.14 or 3.1416. There is a special "button" to enter the symbol π.

yeah its 12x/(sinx+cosx) but in my problem there is no ( ) but yeah its the same thing but what would the equation be to plug in (-pie)

To find f(-π) in the given function f(x) = (12x/sin(x)) + cos(x), you need to substitute x = -π into the function and evaluate it.

Let's substitute x = -π into the function:

f(-π) = (12(-π)/sin(-π)) + cos(-π)

Now, let's simplify step by step. First, let's evaluate the sin(-π) and cos(-π) components:

sin(-π) = 0 (since sine function is zero at -π)
cos(-π) = -1 (since cosine function is -1 at -π)

Replacing these values into our equation, we have:

f(-π) = (12(-π)/0) + (-1)

However, we have a problem because division by zero is undefined. The function is discontinuous at values where the denominator, sin(x), equals zero. In this case, sin(-π) = 0, so the function is undefined at x = -π.

Therefore, f(-π) is undefined.