what is the value of the expression (4.32 x 10^-3) + (6.025 x 10^-3) ?
i came up with either
0.010345*10^-3 or 10.345*10^-3 and when i check them they're both wrong.
well, they are both to the same power, but in the hundredths digit, that is the last significant digit.
10.25 E-3 You cant go further than the least sig digit in 4.32
Actually, I gave you the answer from a measurement standpoint. Your course title Math is not a physical science. So, the math folks assume any number is infinitely precise, so I am not certain. THey might want it in scientific notation, as in 1.025E-2. And, I noticed I made an error, I meant 10.35E-3. Your second answer is correct, mathmetically, but in physical science, you have to concern yourself with precision.
To find the value of the expression (4.32 x 10^-3) + (6.025 x 10^-3), you simply need to add the decimal numbers and the powers of 10 separately. Here's how you can do it:
1. Add the decimal numbers: 4.32 + 6.025 = 10.345.
2. Now, we need to combine the powers of 10. Since the numbers are in scientific notation with the same power of 10 (-3), we can add them directly.
10^-3 + 10^-3 = 2 x 10^-3.
3. Finally, combine the decimal number (10.345) and the power of 10 (2 x 10^-3).
The final answer is 10.345 x 10^-3, which can also be written as 1.0345 x 10^-2 in scientific notation.
Therefore, the correct value of the expression is 1.0345 x 10^-2 or 0.010345.