(3x-5)(2x -8)
5x^2+3
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(3x-5)(2x -8)=
2x*(3x-5)-8*(3x-5)=
6x^2-10x-24x+40=
6x^2-34x+40
To multiply the expression (3x-5)(2x-8), we can use the distributive property. This property states that when you multiply a sum by a number, you can multiply each term inside the sum by that number and then add the products together.
Let's break down the steps to multiply this expression:
Step 1: Multiply the first terms of each binomial: (3x)(2x) = 6x^2.
Step 2: Multiply the outer terms of each binomial: (3x)(-8) = -24x.
Step 3: Multiply the inner terms of each binomial: (-5)(2x) = -10x.
Step 4: Multiply the last terms of each binomial: (-5)(-8) = 40.
Step 5: Combine the products obtained in steps 1-4: 6x^2 - 24x - 10x + 40.
Step 6: Simplify the expression obtained in step 5 by combining like terms: 6x^2 - 34x + 40.
So, the product of (3x-5)(2x-8) is 6x^2 - 34x + 40.