Doubling the voltage across a parallel plate capacitor does not double which of the following?

a. the charge
b. the electric field between the plates
c. the energy stored
d. the electric force on the plates
e. both a and b

is the answer A
if not then how do i do this problem

c. the energy stored

To determine the effect of doubling the voltage across a parallel plate capacitor, we can analyze the different properties of a capacitor and how they are related.

a. the charge: According to the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, the charge stored on a capacitor is directly proportional to the voltage. So, doubling the voltage will indeed double the charge. Therefore, option a is not the correct answer.

b. the electric field between the plates: The electric field between the plates of a parallel plate capacitor is given by E = V/d, where E is the electric field, V is the voltage, and d is the distance between the plates. As we can see, the electric field is directly proportional to the voltage. Thus, doubling the voltage will double the electric field. Therefore, option b is not the correct answer.

c. the energy stored: The energy stored in a capacitor is given by the equation U = 1/2 CV^2, where U is the energy and V is the voltage. As we can see, the energy stored is directly proportional to the square of the voltage. When the voltage is doubled, the energy stored will be quadrupled (double the square). Therefore, option c is incorrect as well.

d. the electric force on the plates: The electric force on the plates of a parallel plate capacitor is given by F = Q*E, where F is the force, Q is the charge, and E is the electric field. Since we know that both the charge (option a) and the electric field (option b) are doubled, the electric force will also be doubled. Therefore, option d is not the correct answer.

By the process of elimination, the correct answer must be option e: both a and b. Doubling the voltage across a parallel plate capacitor does not double the charge (option a) or the electric field between the plates (option b).